MSSQL 计算两个日期相差的工作天数的语句

复制代码 代码如下:

if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_WorkDay]’) and xtype in (N’FN’, N’IF’, N’TF’))

drop function [dbo].[f_WorkDay]

GO

–计算两个日期相差的工作天数

CREATE FUNCTION f_WorkDay(

@dt_begin datetime, –计算的开始日期

@dt_end datetime –计算的结束日期

)RETURNS int

AS

BEGIN

declare @i int

select @i=abs(datediff(dd,@dt_begin,@dt_end))

declare @t table(dt datetime)

if @dt_begin>@dt_end

insert @t select dateadd(dd,number,@dt_end) from master..spt_values

where number<=@i and type=’P’

else

insert @t select dateadd(dd,number,@dt_begin) from master..spt_values

where number<=@i and type=’P’

return(select count(*) from @t where (datepart(weekday,dt)+@@datefirst-1)%7 between 1 and 5)

END

GO

select dbo.f_WorkDay(‘2009-10-10′,’2009-10-1’)

/*

———–

7

(1 個資料列受到影響)

*/

if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_WorkDay]’) and xtype in (N’FN’, N’IF’, N’TF’))

drop function [dbo].[f_WorkDay]

GO

–计算两个日期相差的工作天数

CREATE FUNCTION f_WorkDay(

@dt_begin datetime, –计算的开始日期

@dt_end datetime –计算的结束日期

)RETURNS int

AS

BEGIN

DECLARE @workday int,@i int,@bz bit,@dt datetime

set @workday=0

IF @dt_begin>@dt_end

SELECT @bz=1,@dt=@dt_begin,@dt_begin=@dt_end,@dt_end=@dt

ELSE

SET @bz=0

WHILE @dt_begin<=@dt_end

BEGIN

SELECT @workday=CASE

WHEN (@@DATEFIRST+DATEPART(Weekday,@dt_begin)-1)%7 BETWEEN 1 AND 5

THEN @workday+1 ELSE @workday END,

@dt_begin=@dt_begin+1

END

RETURN(CASE WHEN @bz=1 THEN -@workday ELSE @workday END)

END

GO

select dbo.f_WorkDay(‘2009-10-10′,’2009-10-1’)

/*

———–

-7

*/